When I played with symbol resolution, I constructed a "beautiful" method declaration:

-
When I played with symbol resolution, I constructed a "beautiful" method declaration:
type
  comp = class
  private
    function comp(comp: comp): comp;
  end;

function comp.comp(comp: comp): comp;
begin
  comp := comp;
end;

Wow, It compiles! :D

Comments

  1. Baoquan ZuoAugust 19, 2013 at 11:49 PM

    Panagiotis Drivilas yes. It does make sense only in symbol resolution.

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  2. Anthony FrazierAugust 20, 2013 at 3:49 PM

    So when the symbol comp is referenced from inside the method, is it referring to the result or the parameter? If it's the result, how would one reference the parameter, or is it impossible because of the method name?

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  3. Baoquan ZuoAugust 20, 2013 at 8:27 PM

    Anthony Frazier It refers to the parameter within the scope. however, if you use comp := comp.comp(comp);  the third comp symbol refers to the method, of course.

    ReplyDelete

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